带有饼图标记的散点图
此示例将自定义 '饼图' 作为散点图的标记。
感谢 Manuel Metz 的例子
import numpy as np
import matplotlib.pyplot as plt
# first define the ratios
r1 = 0.2 # 20%
r2 = r1 + 0.4 # 40%
# define some sizes of the scatter marker
sizes = np.array([60, 80, 120])
# calculate the points of the first pie marker
#
# these are just the origin (0,0) +
# some points on a circle cos,sin
x = [0] + np.cos(np.linspace(0, 2 * np.pi * r1, 10)).tolist()
y = [0] + np.sin(np.linspace(0, 2 * np.pi * r1, 10)).tolist()
xy1 = np.column_stack([x, y])
s1 = np.abs(xy1).max()
x = [0] + np.cos(np.linspace(2 * np.pi * r1, 2 * np.pi * r2, 10)).tolist()
y = [0] + np.sin(np.linspace(2 * np.pi * r1, 2 * np.pi * r2, 10)).tolist()
xy2 = np.column_stack([x, y])
s2 = np.abs(xy2).max()
x = [0] + np.cos(np.linspace(2 * np.pi * r2, 2 * np.pi, 10)).tolist()
y = [0] + np.sin(np.linspace(2 * np.pi * r2, 2 * np.pi, 10)).tolist()
xy3 = np.column_stack([x, y])
s3 = np.abs(xy3).max()
fig, ax = plt.subplots()
ax.scatter(range(3), range(3), marker=xy1,
s=s1 ** 2 * sizes, facecolor='blue')
ax.scatter(range(3), range(3), marker=xy2,
s=s2 ** 2 * sizes, facecolor='green')
ax.scatter(range(3), range(3), marker=xy3,
s=s3 ** 2 * sizes, facecolor='red')
plt.show()
参考
本例中显示了下列函数、方法、类和模块的使用:
import matplotlib
matplotlib.axes.Axes.scatter
matplotlib.pyplot.scatter